String.substring() does not consider supplementary characters "□□".substring(0,1) //"?" ![]() You can convert Unicode character to Java String "□".equals(new String(Character.toChars(0x0001F309))) //trueĤ. Represent "□" to String using Unicode \ud83c\udf09 as below and check equality. "□".codePointCount(0,"□".length()) //1, To get the number of Unicode characters in a Java String Length: "□".length() //2, Expectations was it should return 1 the single Unicode character is represented as two adjacent Java characters.ġ. Whichever character (whose Unicode is above U+FFFF) is represented as a surrogate pair, which Java stores as a pair of char values, i.e. Tested in Java-12, should work in all Java versions above 5. ![]() Īdding some more info to the above answers from this post. This design, adopted in the UTF-16 encoding scheme, assigns 1,024 values to 16-bit high surrogates(in the range U+D800 to U+DBFF) and another 1,024 values to 16-bit low surrogates(in the range U+DC00 to U+DFFF). Because 16-bit values were too small to represent all of the Unicode characters in Unicode version 3.1, 32-bit values - called code points - were adopted for the UTF-32 encoding scheme.īut 16-bit values are preferred over 32-bit values for efficient memory use, so Unicode introduced a new design to allow for the continued use of 16-bit values. Later, however, Unicode increased the maximum value to 1,114,111 (0x10FFFF). This design made sense at the time, because all Unicode characters had values less than 65,535 (0xFFFF) and could be represented in 16 bits. ![]() Early Java versions represented Unicode characters using the 16-bit char data type.
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